Question: need help finding solution Solve the system by elimination. 5m + 23; = 17 2m 33; = 2 O No solution 0 Infinite number of
need help finding solution




![with the addition method: {2m+6y = 3 10w+30y= 15 Answer: (E ,C]](https://dsd5zvtm8ll6.cloudfront.net/si.experts.images/questions/2024/11/672f24ff495ac_911672f24ff21b0c.jpg)




Solve the system by elimination. 5m + 23; = 17 2m 33; = 2 O No solution 0 Infinite number of solutions Solve the system by elimination. {4m+ 8y: 4 3m+ 4y: 5 O No solution 0 Infinite number of solutions Solve the system with the addition method: {2m+6y = 3 10w+30y= 15 Answer: (E ,C] ) Enter your answers as integers or as reduced fraction(s) in the form A! B. If there is no solution, type "DNE" in each blank. If there are an infinite number of solutions, specify their form in the blanks in terms of x (eg. (x, 2x-3)). \fA bank loaned out 517,500, part of it at the rate of 12% annual interest, and the rest at 5% annual interest. The total interest earned for both loans was $1,190.00. How much was loaned at each rate? 5:] was loaned at 12% and S was loaned at 5%. The admission fee at an amusement park is $1.75 for children and $6.80 for adults. On a certain day, 292 people entered the park, and the admission fees collected totaled 51319. How many children and how many adults were admitted? number of children equals :] number of adults equals :] Mark invests $7600 in two different accounts. The first account paid 10 96, the second account paid 5 % in interest. At the end of the first year he had earned $610 in interest. How much was in each account? 5:]at1096 5:]at596 You need a 55% alcohol solution. 0n hand, you have a 175 mL of a 10% alcohol mixture. You also have 80% alcohol mixture. How much of the 80% mixture will you need to add to obtain the desired solution? You will need :] mL of the 80% solution You have one type of chocolate that sells for $1.60/lb and another type of chocolate that sells for $7.40! lb. You would like to have 46.4 lbs of a chocolate mixture that sells for $2.90! lb. How much of each chocolate will you need to obtain the desired mixture? You will need [:] lbs of the cheaper chocolate and C] lbs of the expensive chocolate
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