Question: Need help implementing the generate _ kFold function, which takes in the number of training examples n and the number of folds k and returns

Need help implementing the generate_kFold function, which takes in the number of training examples n and the number of folds k and returns a list of k folds, where each fold takes the form (training indices, validation indices).
For instance, if n =3 and k =3, then we have three indices [0,1,2] and we are trying to split it k =3 times to obtain different training/validation splits. One possible output of the the function is [([0,1],[2]),([1,2],[0]),([0,2],[1])]. It is possible that k might not divide n with remainder 0. In that case, you can divide n k-1 times fully and have the remainder constitute the final fold. For instance, if n =5 and k =4, one possible output is [([1,2,3,4],[0]),([0,2,3,4],[1]),([0,1,3,4],[2]),([0,1,2],[3,4])].
Ensure that no two folds have the same indices as it is wasteful to train a model on the same training/validation split again.
One possible algorithm: divide the list of n indices into k parts and loop k times, collecting all but 1 parts into the training set for Please hthat fold and leaving that part as the validation set.
Please help me replace # YOUR CODE HERE
def generate_kFold(n, k):
"""
Generates [(training_indices, validation_indices),...] for k-fold validation.
Input:
n: number of training examples
k: number of folds
Output:
kfold_indices: a list of length k. Each entry takes the form (training indices, validation indices)
"""
assert k >=2
kfold_indices =[]
# YOUR CODE HERE
raise NotImplementedError()
return kfold_indices

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!