need help to solve, please see attached

Consider the following. h ( x ) = ex- - 4 Find h '(x). h' ( x ) = 2x072 X Solve h '(x) = 0 for x. X = 2xp12 X Check which variable(s) should be in your answer. Find h(0), h(-2), and h(2). h(0) = 3 X h( - 2) = e 4 - 4 X h (2) = - 4 X Find the absolute extrema of the function h(x) = ex- - 4 on [-2, 2] Absolute maximum value: -2,1 at X = + 2,1 X X You may have mistyped. Check for a missing variable. Absolute minimum value: 0 at X = X X