Question: Need help with all three questions //SquareContainer2.cpp #include #include using namespace std; #include SquareContainer2.h // Prefix form of next operator SquareContainer::iterator SquareContainer::iterator::operator++() { // Don't

Need help with all three questions  Need help with all three questions //SquareContainer2.cpp #include #include using namespace

//SquareContainer2.cpp

#include

#include

using namespace std;

#include "SquareContainer2.h"

// Prefix form of "next" operator

SquareContainer::iterator

SquareContainer::iterator::operator++()

{

// Don't do anything if we're already past the end

if (y ySize) {

if (++x >= theContainer->xSize) {

x = 0;

y++;

}

}

return *this;

}

// Postfix form of "next"

SquareContainer::iterator

SquareContainer::iterator::operator++(int)

{

iterator returnValue = *this;

// Don't do anything if we're already past the end

if (y ySize) {

if (++x >= theContainer->xSize) {

x = 0;

y++;

}

}

return returnValue;

}

// Returns the current item

int& SquareContainer::iterator::operator*()

{

// If we're past the end, it's really an error. You could throw an

// exception, if you like. Make sure you document the iterator's

// behavior in these circumstances.

if (y >= theContainer->ySize) {

cerr

exit(EXIT_FAILURE);

}

return theContainer->contents[x][y];

}

bool SquareContainer::iterator::operator==(const iterator& rhs) const

{

return (theContainer == rhs.theContainer) && (x==rhs.x) && (y==rhs.y);

}

bool SquareContainer::iterator::operator!=(const iterator& rhs) const

{

return (theContainer != rhs.theContainer) || (x != rhs.x) || (y != rhs.y);

}

//IteratorTest.cpp

#include

using namespace std;

#include "SquareContainer2.h"

int main()

{

// You create a container like so:

SquareContainer mc;

// and use it in various ways:

SquareContainer::iterator ci = mc.begin();

unsigned i = 1;

while (ci != mc.end()) {

cout

*(ci++) = i++;

}

for (SquareContainer::iterator ci = mc.begin();

ci != mc.end();

++ci) {

cout

}

}

//SquareContainer.h

#pragma once

class SquareContainer {

public:

class iterator; // forward declaration

friend class iterator; // friend declaration

/*!

@class iterator

This is a nested class. Note that it is in the public section of

SquareContainer

*/

class iterator {

public:

/*!

Initializes the iterator by associating it with a

SquareContainer object, starting it at the beginning.

*/

iterator(SquareContainer* c, unsigned xloc = 0, unsigned yloc = 0) :

theContainer(c), x(xloc), y(yloc) {}

// You may need a copy constructor; we don't have it here

// iterator(const iterator& it);

// Prefix form of "next" operator

iterator operator++();

// Postfix form of "next"

iterator operator++(int);

// Returns the current item

int& operator*() const;

// Comparison operators

bool operator==(const iterator& rhs) const;

bool operator!=(const iterator& rhs) const;

private:

/*! Keep track of where we are in theContainer */

unsigned x, y;

/*! The SquareContainer object this iterator is associated with */

SquareContainer* theContainer;

};

//Returns iterator that refers to first item, using iterator constructor

iterator begin(void) { return iterator(this); }

const iterator end(void) { return iterator(this, 0, ySize); }

private:

static const unsigned xSize = 5;

static const unsigned ySize = 5;

int contents[xSize][ySize];

};

1. Question: Look at the code in IteratorTest.cpp. What do you think it does? Compile the code (do you need to do anything "unusual" to get it to compile?) and run it. Does it do what you think it would? Take Away: Reminder of how to template class compilation, understanding of code. 2. Question: Why do the iterator increment operators return an iterator? How do the two increment operators differ? Is the iterator they return allocated dynamically, auto, or something else? - Take Away: What does it mean to return a reference to self (in this case, and, in general, remember, overloaded operators typically return self). 3. Interactive Coding and Question: Change SquareContainer::iterator::operator*() so that it is a const method. What is this supposed to mean? When you try to compile and run the program, what happens? Does this appear to be consistent with the declaration of that operator as const? Why or why not? In your opinion, should that operator be declared const? Take Away: Understanding of "const", when to use, and why to (or not to) use

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