need help with question 6 and 7

webassign.net ) C The AD Interview - YouTube "A Larson 7th Sec. 4.1 - Math 181, section 6407, Summer 1 2021 | WebAssign Find the absolute extrema of the function on the closed interval. g (x) = _ 5x2 X - 6 [-3, 2] minimum ( x, y ) = (smaller x-value) minimum ( x, y ) = (larger x-value) maximum ( x, y ) = 7. [-/6 Points] DETAILS LARCALCET7 4.1.031.EP. MY NOTES Consider the following function and closed interval. y = 3x2/3 - 2x, [-1, 1] Find y'. Find the critical number of y in (-1, 1) and evaluate y at this critical number. (x, y) = Evaluate y at each endpoint of [-1, 1]. left endpoint ( x, y ) = right endpoint ( x, y ) = Find the absolute extrema of the function on the closed interval [-1, 1]. minimum ( x, y ) = maximum ( x, y ) = (