Question: Need help with revision from algebra: Teachers message: #5 - Please explain how you arrived at the equation 4.9 t 2 - 20 t =
Need help with revision from algebra:
Teachers message:
#5 - Please explain how you arrived at the equation 4.9 t2- 20 t = -(s-60).What does -(s-60) represent?
#8 - Please give an equation in the form ax2+ bx + c = 0 with numerical values for a, b, and c.
Original question:
5. A ball is launched upward at 20 meters per second (m/s) from a 60 meter tall platform. The equation for the object's heightsat timetseconds after launch iss(t) = -4.9t2+ 20t + 60, wheresis in meters.What is the maximum height of the object?
8)Give an example of a quadratic equation which would have only 1 solution. Write the equation in standard form.(You may not use an example from this lesson or any other lesson in this course.)
My answers:
s = shall be the height at which it is above ground
s = 60 + 20 t - 4.9 t2
at t = 0
s = 60
When will this reach the bleak on earth?
When s = 0
4.9 t2- 20 t -60 = 0
t = 6.09 or - 2.01
t = 6.09 will be used
(x-1)(x-b)=0
x-1=0
x-1+1=0+1
x=1
x-b=0
x-b+b=0+b
x=b
x=1, x=b
please write it out on computer, i cannot read handwriting.
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