Question: need step by step. As in the figure below, suppose that a salt solution of 4 9/L is pumped into Tank 1 at the rate
need step by step.

As in the figure below, suppose that a salt solution of 4 9/L is pumped into Tank 1 at the rate of 3 L/min, the solution in Tank 2 is pumped out at the same rate, but the solutions in the two tanks are mixed by pumping from Tank 1 to 2 at /12 = 4 L/min and from Tank 2 to 1 at /21 = 1 L/min. 1 12 X , 121 Tank 1 Tank 2 Suppose both tanks initially contain 20 L of salt solution, but the solution in Tank 1 has 40 g of salt and the solution in Tank 2 has 60 g of salt. Find the amount of salt in each tank at time t. (x1(t), x2(t) ) = What happens to the concentration in both tanks as t - co? O Tank 1 will eventually have a higher concentration of salt. O Tank 2 will always have a higher concentration of salt. O The two tanks will eventually have a uniform concentration of salt
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
