Question: need this asap thanks Consider the function f (x) = ex + 2*+ 2cos x- 10 Use the secant method with initial values X1 =

need this asap thanks

Consider the function f (x) = ex + 2"*+ 2cos x- 10 Use the secant method with initial values X1 = 1 and X2 = 4 to approximate the root of the function at the n = 4 iteration. What would be the latest value of the absolute approximate error at the n = 4 iteration rounded off to six decimal places

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