Question: need this solved simply in C language. not c++ please be clear thanks will upvote A year in the modern Gregorian Calendar consists of 365

need this solved simply in C language. not c++
please be clear thanks will upvote
need this solved simply in C language. not c++ please be clear
thanks will upvote A year in the modern Gregorian Calendar consists of

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712 and 2016 Write a program that takes in a year and determine whether that year is a leap year Ex If the input is 1712, the output is 1712 - leap year Ex: If the input is 1913, the output is 1913 - not a leap year #include #include int main(void) { int inputYear; bool isLeapYear = false; scanf("%d", &inputYear); /* Type your code here. */ 2 1 2 3 42 return 0

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