Need to know the % difference on both problems. I marked both with a Question(?) mark. Need answers for those two please

Student Name Section Date Report on Laboratory Experiment "Rotational Equilibrium" DATA TABLES Part I. Testing the condition of rotational equilibrium. Mcth (8) = 15.9 Table 1 MIT(g) = 100 g + Meth Xo (m ) = 104 M170 MIT MIT X1 M2T(8) = 50g + Meth (8) (8) (kg) M270 (m) M2T M2T X2 1159 (8) 0 . 1159) (8) (kg) (m) 100 0.30 50 65. 9 0.659 . 865 F1 = MIT(kg) xg(m/s2) d1 = Xo - X1 N F2 = M2T (kg) xg(m/s2) d2 = X2 - Xo (m) (N) (m) 1 . 14 0, 204 6. 46 0 . 361 Tccw = 11 = F1(N) di(m) Tow = 12 = F2(N) d2(m) (N.m) (N.m) + 0.283 2. 53 % Difference between tecw and tow Meth: Mass of clamp plus hanger Xo: Position of pivot point d1: lever arm of force F1 X1: Position of 100 g mass d2: lever arm of force F2 X2: Position of 50 g mass Part II. Determination of the mass of an unknown object. Table 2 Moth ( kg) = 010159 Xo (m) =504 Mu-measured X1 d1 = Xo - X1 Mk X2 d2 = X2 - Xo (kg) (m) (m) ( kg ) (m) (m) 0ro 679 0.30 0. 204 - 050 0.755 0 251 Mu-calculated (kg) using equation (3) 0. 0652 F. % Difference between Mu-calculated and Mu-measured ? Meth: Mass of clamp plus hanger Xo: Position of pivot point Mk: Mass of known object X1: Position of unknown mass Mu-calculated: Mass unknown calculated X2: Position of known mass Mu-measured: Mass unknown measured d1: lever arm of force F1 d2: lever arm of force F2 QUESTION: Do results from the first experiment support the validity of the condition of rotational equilibrium? Justify your answer. 47