**Need to use Binary IO Codes**

Write a Hex Viewer method with the following header: private static void viewHex(String filename) The method reads bytes from filename and displays them in hex representation. The output should be formatted as in the example below, i.e., each line consists of 8 pairs of hex numbers, then |, then another 8 pairs. Use Integer.toHexString() to convert a byte into a string representing the equivalent hex. Use a try statement to handle IOException and display a simple error message if an I/O exception occurs.

Sample run:

89 50 4E 47 0D 0A 1A 0A | 00 00 00 0D 49 48 44 52

00 00 00 02 00 00 00 02 | 08 06 00 00 00 72 B6 0D

24 00 00 00 01 73 52 47 | 42 00 AE CE 1C E9 00 00

00 04 67 41 4D 41 00 00 | B1 8F 0B FC 61 05 00 00

00 09 70 48 59 73 00 00 | 0E C4 00 00 0E C4 01 95

2B 0E 1B 00 00 00 1B 49 | 44 41 54 18 57 63 BC 7A

FA D8 FF 1F DF BF 33 30 | BD FA F0 9E E1 F3 AF 9F

0C 00 73 86 0B FE AA 7D | 68 4E 00 00 00 00 49 45

4E 44 AE 42 60 82