Net shear force on frames $1-1$ and $4-43$ points due to earthquake shear in y$-$direction is given by

$V_{y1}=-(0-0\mathrm{.}2)V$;$V_{y4}=(0-0\mathrm{.}2)V$

$V_{y1}=(0\mathrm{.}2-0\mathrm{.}5)V$;$V_{y4}=(0\mathrm{.}5-1)V$

$V_{y1}=-(0\mathrm{.}2-0\mathrm{.}5)V$;$V_{y4}=(0\mathrm{.}5-1)V$

$V_{y1}=(0-0\mathrm{.}2)V$;$V_{y4}=-(0-0\mathrm{.}2)V$