Newton's second law can be expressed as the formula known as the equation of motion.

$F=ma$

where $F$ is the force, or sum of forces, acting on the particle; $m$ is the mass of the particle; and $a$ is the acceleration of the particle

Figure

$1$ of $2$

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Part C

Two players hit an air hockey puck simaltaneously. One player hits the puck with a force $F_1=785N$ at an angle $=29\mathrm{.}5$ The other player hits the puck with a force $F_2=6\mathrm{.}65N$ at an angle $=595.($Figure $2)$ If the puck has a mass $m_1=51\mathrm{.}0g,$ what is $a,$ the acceleration of the puck, and $,$ the angle of the puck's motion? The friction between the puck and the table's surface is negligible.

Express your answers numerically to three significant figures in meters per second squared and degrees separated by a comma.

View Available Hint$($s$)$

$\backslash$table$[[,A,$darruarr,vec,h$,,0,,?,],[a_{,}=,,,,,,,,,\frac{m}{s^2},]]$

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