> Next question You can retry this question below A normal distribution has a mean of 31 and a standard deviation of 4. Find the probability that a randomly selected x-value from the distribution is in the given interval 15 19 23 27 31 35 39 43 X Q 68 * (to the nearest percent) 15 19 23 27 31 35 30 43 X Q 48 * * (to the nearest tenth of a percent)The arrows can only be dragged to z scores that are accurate to 1 place after the decimal point (these values correspond to the tick marks on the horizontal axis). So round all z scores to 1 decimal place, if necessary. (a) Sketch the region corresponding to the statement P(z c) = 0.25. Shade: Right of a value v . Click and drag the arrows to adjust the values. -3 2 0.2