Question: No Daily feed: 7 0 tons = 7 0 tons ? 1 0 h r s = 7 tons ? h r Q = 7

No
Daily feed: 70 tons
=70 tons ?10hrs
=7 tons ?hr
Q=7000kghr
Operation hours: 10 his /day
0.495
(1-x-y-2)kg, excess NaOH
Mass balance: 7000kghr
In reactor.
Mass flow rate of UCO=17000kghr
=7000kghr
Reaction: 0.1+3NaOHlongrightarrow Glycerine +3 soap , DOF :5-5=0
]=21(12)+38(1)+6(16)[386
Mw of soap:
:6(12)+11(1)+2(16)+23
=138
MW of glycerine =3(12)+8(1)+
=92
Oil: 1000=z(386)
=18.135
NaOH: M3(1-x-y-2)=M2(0.3)-3(40)
Glycerine: M3(x)=(92)
Soap: M3(y)=3(133)
H2O:M2(0.7)=M3(z)
M3x=1668.42,M2y=7507.89,0.7M2=M3z
 No Daily feed: 70 tons =70 tons ?10hrs =7 tons ?hr

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