Question: ?(n=o to ?) 1/[(sqrt(2)^n] so I found that it was convergent because according to geometricseries test r= 1/sqrt2 which is less than one, so itconverges.

?(n=o to ?) 1/[(sqrt(2)^n]

so I found that it was convergent because according to geometricseries test r= 1/sqrt2 which is less than one, so itconverges.

because it converges, what is the sum of the series?

THANKS!!!!!!!!!!!

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