Question: NOTE: PLEASE ANSWER THE QUESTION IN CLEAR AND AS POSSIBLE AS SIMPLE STEPS. I APPRECIATE IF YOU COULD USE COMMENTS. IN COMPLETE AND WRONG ANSWERS
NOTE: PLEASE ANSWER THE QUESTION IN CLEAR AND AS POSSIBLE AS SIMPLE STEPS. I APPRECIATE IF YOU COULD USE COMMENTS. IN COMPLETE AND WRONG ANSWERS WILL GET THUMBS DOWN.
THANK YOU.
For the given program below calculate the function for the runtime and categorize it as constant, linear, log, quadratic
// PROGRAM STARTS HERE
#includeusing namespace std; struct N { int val; N *next; }; int main() { int NUM[5]= {5,8,6,13,14}, A[5] = {-1,-1,-1,-1,-1}; for(int k=0; k<5; k++) { if(A[k]% 5 == -1) A[(NUM[k]% 5)] = NUM[k]; else if((A[k+1]% 5 == -1) && k<4 ) A[((NUM[k]+1)% 5)] = NUM[k]; else if((A[k+2]% 5 == -1) && k<3) A[(NUM[k]% 5)+2] = NUM[k]; else if((A[k+3]% 5 == -1)&& k <2) A[(NUM[k]% 5)+3] = NUM[k]; else if(A[k+4]%5 == -1) A[(NUM[k+4]%5)] = NUM[k]; else if(A[k-4]% 5 == -1) A[(NUM[k]% 5)-4] = NUM[k]; else if(A[k-3]% 5 == -1) A[(NUM[k]% 5)-3] = NUM[k]; else if(A[k-2]% 5 == -1) A[(NUM[k]% 5)-2] = NUM[k]; else if(A[k-1]% 5 == -1) A[(NUM[k]% 5)-1] = NUM[k]; } for(int k=0; k<5; k++) { cout<
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