NOTE: Solve Using Python

$$ YOU CANNOT USE ANY BUILT$-$IN FUNCTION EXCEPT len IN

PYTHON. $[$negative indexing, append is prohibited$]$

$$ You can use the attribute $$shape$$ of numpy arrays

$$ YOU HAVE TO MENTION SIZE OF ARRAY WHILE INITIALIZATION

$$ YOUR CODE SHOULD WORK FOR ANY VALID INPUTS. $[$Make

changes to the Sample Inputs and check whether your program works

correctly$]$ here is the code : def play$\_$game$($arena$)$:

#TO DO

arena$=$np$.$array$([[0,2,2,0],$

$[50,1,2,0],$

$[2,2,2,0],$

$[1,100,2,0]$

$])$

print$\_$matrix$($arena$)$

play$\_$game$($arena$)$

#This should print

#Points Gained: $6.$ Your team is out.

print$(".....................")$

arena$=$np$.$array$([[0,2,2,0,2],$

$[1,50,2,1,100],$

$[2,2,2,0,2],$

$[0,200,2,0,0]$

$])$

print$\_$matrix$($arena$)$

play$\_$game$($arena$)$

#This should print

#Points Gained: $14.$ Your team has survived the game. Do in this provide code.. Here is The Question: Game Arena:

Suppose you and your friends are in the world of 'Alice in Borderland' where

you decided to take part in a game and entered the game arena. As a team,

you need to gain at least $10$ points in order to keep surviving in the

borderland. Otherwise, you will be out of the game and your team will be

banished for good. Now, the arena has a $2$D array like structure where players

of a team are given certain positions with values that are multiples of $50.$ By

staying in these positions, every player can gain points from the cells above,

below, left and right $($not diagonally$)$ only if those cells contain $2[$The cells

containing $1s$ and $0s$ are to be avoided$].$ For each player, add from these cells

containing $2s$ to your total points for the team to keep on surviving in

borderland. Be careful about corner cases. Your task is to write a method

which tells us whether your team is out or has survived the game.

$|0|200|2|0|0|$

Explanation:

Player with value $50$ has $2$ in the cell above, cell below and the right cell $(3$ cells$).$

Player with value $100$ has $2$ in the cell above and the cell below $(2$ cells$).$ Player with

value $200$ has $2$ in the above cell and right cell $(2$ cells$).$ So in total, they gained

$(3+2+2)**2=14$ points and survived the game.

Note: For the cell with value $2$ that is common between $2$ players in position $(2,1),$ both

gained $2$ points each, so it's not like if one player already added those $2$ points, another

player cannot.