For this problem, XXX is the final three digits of your University N number. A storage...

 

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For this problem, XXX is the final three digits of your University N number. A storage tank supplies water to a community. The length of the final segment of pipe, L, is 1000+XXX ft. The valve to the branch line is closed. Flowrates vary throughout the day following the rural demand pattern shown in the class lesson (repeated below). The maximum flowrate is 450*(1.XXX) gpm. To satisfy local codes, the pressure at point A must not drop below 60 psi. (a) Calculate the maximum flowrate. Use the rural demand pattern curve to determine the flowrate at each hour. Document your calculations (explain your method and show a sample calculation) and present the hourly flowrates in a table. (b) Determine the total volume (gal, ft³) of water that is used in a day. 250% 200% 150% 100% (c) Without doing any calculations, determine which scenario will lead to the lowest pressure at point A. Specifically, use your understanding of the equations used for pipe flow calculations to determine which flowrate and which water depth in the tank (depth can range from 4 to 12 ft) would lead to the lowest pressure at A. State your answer and provide a clear explanation of your rationale. 50% 0% 6 ft 0:00 3:00 4 to 12 ft 600 ft with 15 90° elbows 6:00 h 9:00 All pipe is 6-in.-diameter plastic flanged fittings Branch line Rural pattern 12:00 L 15:00 (d) Using the flowrate and water depth selected in part (c), determine the tank elevation denoted by variable h on the figure which will lead to a pressure of 60 psi at point A. Use the Hazen Williams equation. Document your work, including your selection of minor loss coefficients. (e) Draw the HGL and EGL to scale on a full sheet of paper. Document all supporting calculations. 18:00 A Main line 21:00 0:00 For this problem, XXX is the final three digits of your University N number. A storage tank supplies water to a community. The length of the final segment of pipe, L, is 1000+XXX ft. The valve to the branch line is closed. Flowrates vary throughout the day following the rural demand pattern shown in the class lesson (repeated below). The maximum flowrate is 450*(1.XXX) gpm. To satisfy local codes, the pressure at point A must not drop below 60 psi. (a) Calculate the maximum flowrate. Use the rural demand pattern curve to determine the flowrate at each hour. Document your calculations (explain your method and show a sample calculation) and present the hourly flowrates in a table. (b) Determine the total volume (gal, ft³) of water that is used in a day. 250% 200% 150% 100% (c) Without doing any calculations, determine which scenario will lead to the lowest pressure at point A. Specifically, use your understanding of the equations used for pipe flow calculations to determine which flowrate and which water depth in the tank (depth can range from 4 to 12 ft) would lead to the lowest pressure at A. State your answer and provide a clear explanation of your rationale. 50% 0% 6 ft 0:00 3:00 4 to 12 ft 600 ft with 15 90° elbows 6:00 h 9:00 All pipe is 6-in.-diameter plastic flanged fittings Branch line Rural pattern 12:00 L 15:00 (d) Using the flowrate and water depth selected in part (c), determine the tank elevation denoted by variable h on the figure which will lead to a pressure of 60 psi at point A. Use the Hazen Williams equation. Document your work, including your selection of minor loss coefficients. (e) Draw the HGL and EGL to scale on a full sheet of paper. Document all supporting calculations. 18:00 A Main line 21:00 0:00

Answer rating: 100% (QA)

a To calculate the maximum flowrate you need to use the rural demand pattern curve provided in the class lesson Start by determining the flowrate at e... View the full answer