Question: Now, assume going forward that the position is given by the equationx(t)=0.2t32.4t2+7.2t5x(t)=0.2t32.4t2+7.2t5. How many times are the person's position, velocity, and acceleration equal to zero?

Now, assume going forward that the position is given by the equationx(t)=0.2t32.4t2+7.2t5x(t)=0.2t32.4t2+7.2t5. How many times are the person's position, velocity, and acceleration equal to zero?

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