Now let's apply a potential difference or voltage across a parallel-plate capacitor and calculate the resulting charge and electric field. Suppose the plates of a parallel-plate capacitor are 5.00 mmmm apart and 2.00 m2m2 in area. If a potential difference of 10.0 kVkV is applied across the capacitor, compute (a) the capacitance, (b) the charge on each plate, and (c) the magnitude of the electric field in the region between the plates.

(1) Repeat the example for a capacitor with the same area and potential difference, but with a plate separation of 3.50 mmmm. What is the capacitance?Express your answer with the appropriate units.

(2) What would be the charge on each plate described in Part A?Express your answer with the appropriate units.

(3)What is the magnitude of the electric field in the region between the plates described in Part A?Express your answer with the appropriate units.

Is the electric-field magnitude between the plates larger or smaller than that for the original capacitor?

larger

smaller