Now that we know vec$(F_2)$ and vec$(F_3),$ we can find the net force on particle $q_1$ by adding these two forces together.

vec$(F_2)=-14\mathrm{.}4N,$vec$(F_3)=2\mathrm{.}28N$

$,F=,N$

Be sure to include the direction of the force $--$ a minus sign if pointing to the left or $a+$ sign if pointing to the right.