Now we are to find

P(32 x 36).

Graphically, this will be another rectangle whose area can be found by multiplying the width and the height. The height was previously found to be 0.10, so the width is needed.

The width is the distance from the left endpoint to the right endpoint. The distance, and thus the width of the rectangle, from 32 to 36 is ____________ . Find the area of this rectangle, which is also P(32 x < 36).

P(32x<36)= Width times height

=(________) (.10)

=_________