Now, we will find a formula for the sequence $4,512,1223,3134,6845,129564,512,1223,3134,6845,12956$

We know that $02=0,12=1,22=4,32=9,42=16,52=25,02=0,12=1,22=4,32=9,42=16,52=25,$ and $03=0,13=1,23=8,33=27,43=64,53=125,03=0,13=1,23=8,33=27,43=64,53=125,$

So$,$ for the numerator, we can use the $($No answer given$)$squarescubes to our advantage since $0+0+=4,1+=4,1+44=5,=5,($No answer given$)2^22^3++=12,=12,($No answer given$)3^23^3++44=31,=31,($No answer given$)4^24^3++=68,=68,$ and $($No answer given$)5^25^3++44=129=129$

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So$,$ a formula for the numerator of the sequence is $$

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Additionally, a formula for the denominator of the sequence is

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So$,$ a formula for our sequence, starting at n$=0$n$=0$ is an$=$an$=$ n$3+4$n$3+4/11==$

In each of the $3$ lines above, your answer should be in terms of nn

This sequence $($No answer given$)$convergesdiverges

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