Now Write Some Code: Please write the code with clion c$99$

The code as it is now gives a $10\%$ discount for six packs. Your task is to modify it so that it gives a $15\%$

discount for a case of $24$ bottles. It should maximize the savings by giving the maximum number of full

cases, then the maximum number of six packs from the number of bottles that didn't make it into cases, then

the number of left over bottles.

Here's some test data to check against:

If you have trouble getting the calculations to work, use the debugger to look at intermediate calculations to

see where you are going wrong.

Answer the questions for this part of the project in Gradescope.

Fix up the output

We really want to tell the person satisfying this order how many things to gather. Modify the printf statement

$($and make no other changes!$)$ so that your output looks like this:

Cases: $1,$ Six packs: $3,$ Singles: $1.$ The total cost is $$48\mathrm{.}50$

Your output must match that format EXACTLY. Notice that the printf statement is rounding the cost to the

nearest penny and has added a dollar sign to the total cost. Here is the starting code that is given: #include

#define COST$\_$PER$\_$BOTTLE $1\mathrm{.}29$

#define SIX$\_$PACK$\_$DISCOUNT $0\mathrm{.}10$

#define COST$\_$PER$\_$SIX$\_$PACK COST$\_$PER$\_$BOTTLE $*(1-$

SIX$\_$PACK$\_$DISCOUNT$)*6$

int main$()\{$

int number$\_$of$\_$bottles;

int number$\_$of$\_$bottles$\_$left;

int number$\_$of$\_$six$\_$packs;

double total$\_$cost;

printf$("$Please enter the number of bottles:

$")$;

scanf$("\%$d$",$ &number$\_$of$\_$bottles$)$;

number$\_$of$\_$six$\_$packs $=$ number$\_$of$\_$bottles $/6$;

number$\_$of$\_$bottles$\_$left $=$ number$\_$of$\_$bottles $\%6$;

total$\_$cost $=$ number$\_$of$\_$bottles$\_$left $*$

COST$\_$PER$\_$BOTTLE $+$ number$\_$of$\_$six$\_$packs $*$

COST$\_$PER$\_$SIX$\_$PACK;

printf$("$The total cost is $\%10\mathrm{.}2$f$",$ total$\_$cost$)$;

return $0$;