nts$)$ Consider the line $L(t)=($:$t-1,t-3,2-5t$:$).$ Then:

$L$ is $$ to the plane $10z-(2x+2y)=-36$

$L$ is $$ to the plane $3y-2x+3z=-2$

$L$ is $$ to the plane $x+5y-5z=10$

$L$ is $$ perpendicular to the plane $1\mathrm{.}5x+1\mathrm{.}5y-7\mathrm{.}5z=4\mathrm{.}5$