Nutrient Requirements Calculation Homework Assignment b) Assume you are at the barn and wish to make 10 lbs of the 13% CP hay mixture. Accounting for moisture content, how many pounds of each hay will you add together? 77 153.503 x 100 = 50.327 76/153=.497 x 100 = 49.673 10 X.503 5.03 lbs 10 X 497=4.91lbs You wish to mix 2000 lbs of a corn and soybean meal-based diet that will be 12% crude protein. a) On a dry matter basis, what percentage of each feedstuff will you combine to accomplish this? Corn 88 5BM 188-12 794 parts corn 76 parts SBM 79 + 76 2000 x 510 = 2000 X.490 = 155 total parts 79/155.510 x 100 = 51% 76/155 = .490 x 100 = 49% 911 -) Assume you are ready to mix the ingredients, accounting for moisture, how many pounds of each will you add to the feed mixer? 5.0004 (2) How many pounds of protein? 0.667165 1020 lbs corn 980 lbs SBM 25.5 = .913 *194 5.556165 ii) In the amount that you weighed into the trough: (1) How many pounds of dry matter? 2.921*100=512) Assume you have now correctly mixed the corn