Oat $a,b,c,d$ be integers and $m$ be a positive integer. If $a-=b(modm)$ and $c-=d(modm),$

then prove, $(20$ pts$)$

a$.a+c-=b+d(modm)(10pts)$

b$.ac-=bd(modm)(10pts)$

Answer:

Let $a,b,c,d$ be integers and $m$ be a positive integer. If $a-=b(modm)$ and $c-=d(modm),$

then prove, $(20$ pts

a$.a+c-=b+d(modm)(10pts)$

b$.ac-=bd(modm)(10pts)$

Answer: Please show how to get the answer and explain the steps if you have the change