Question: Observe the following expression and provide the correct choice without explanation: let z = (fun x -> x mod 2) in let f a b

Observe the following expression and provide the correct choice without explanation: let z = (fun x -> x mod 2) in let f a b = if a true then [z] else b in let z = (fun x -> x && true) in f z Question 6.1 Q6.1 1 Point Grading comment: What is the type of the expression? Choice 1 of 5: (int -> int) list -> (int -> int) list Choice 2 of 5: Type Error Choice 3 of 5: (int -> int) -> (int -> int) Choice 4 of 5: (bool -> bool) list -> (bool -> bool) list Choice 5 of 5: (bool -> bool) -> (int -> int) list -> (int -> int) list

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