Question: On a 32-bit MIPS machine, you need to execute the following single-precision floating point arithmetic instructions: 1. 3.5e25 * 3.5e25 / 12.0e20 2. 13.2e-30 *

On a 32-bit MIPS machine, you need to execute the following single-precision floating point arithmetic instructions:
1. 3.5e25 * 3.5e25 / 12.0e20
2. 13.2e-30 * 3.5e25
3. 13.2e-20 / 3.5e25 + 5.7e8
Do any of the above operations overflow or underflow? If so, can they be rewritten so they work? Note: all the above expressions are in base 10, the notation eNNN means 10 raised ot he NNN power.
On a 32-bit MIPS machine, you need to execute the following single-precision floating point arithmetic instructions: 1. 3.5e25 * 3.5e25 12.0e20 2. 13.2e-30 3.5e25 3, 13.2e-20 / 3.5e25 + 5.7e8 -26 13.2 Do any of the above operations overflow or ten so they work? Note: above eNNN means 10 raised to the NNN power underflow? If so, can all the above expressions are in base 10, they be rewrit- the notation On a 32-bit MIPS machine, you need to execute the following single-precision floating point arithmetic instructions: 1. 3.5e25 * 3.5e25 12.0e20 2. 13.2e-30 3.5e25 3, 13.2e-20 / 3.5e25 + 5.7e8 -26 13.2 Do any of the above operations overflow or ten so they work? Note: above eNNN means 10 raised to the NNN power underflow? If so, can all the above expressions are in base 10, they be rewrit- the notation
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