On July $21$ at $12$:$00$ P$.$M$.$ solar time, what percentage of the window is shaded with a $6-$inch setback and without considering the overhang in Shreveport, LA$,$ if:

The window height is $7$ ft$.$

The surface azimuth needs to be calculated for $30$ west of south.

The window is rotated $10$ towards the north.

The solar altitude angle $()$ needs to be recalculated with an additional factor of atmospheric refraction correction of $0\mathrm{.}8.$

Assumptions:

Latitude $()$: $32\mathrm{.}47$ N

Window dimensions: $4$ ft wide $($W$),7$ ft tall $($H$)$

Setback distance $()$: $6$ inches $(0\mathrm{.}5$ ft$)$

Overhang depth: $2$ ft

Distance above window: $2\mathrm{.}5$ ft

Declination $()$: $20\mathrm{.}6$

Hour angle $()$: $0\mathrm{.}0$

Surface azimuth $()$: Calculate for $30$ west of south

Additional Variables:

The window is rotated $10$ towards the north.

Recalculate the solar altitude angle $()$ with an atmospheric refraction correction of $0\mathrm{.}8.$

options:

$53\mathrm{.}67\%$

$44\mathrm{.}93\%$

$39\mathrm{.}00\%$

$25\mathrm{.}42\%$