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Consider the differential equations = -x + ay + xy = b-ay-xy In mathematics, a stationary point of a differentiable function of one variable is a point on the graph of the function where the function's derivative is zero. Solve for the stationary points of the equations by the relaxation method when a = 1 and b = 2; -x + ay + xy = 0 (1), b-ay - xy = 0 (2) So you can check your results, the analytical solution is clearly x=b, y= 22 a + b2 You have two choices of how to solve for x and y, depending on which two of the equations you solve for x and the other y, or vice vera. Provide both ways as different functions in your program. Consider the differential equations = -x + ay + xy = b-ay-xy In mathematics, a stationary point of a differentiable function of one variable is a point on the graph of the function where the function's derivative is zero. Solve for the stationary points of the equations by the relaxation method when a = 1 and b = 2; -x + ay + xy = 0 (1), b-ay - xy = 0 (2) So you can check your results, the analytical solution is clearly x=b, y= 22 a + b2 You have two choices of how to solve for x and y, depending on which two of the equations you solve for x and the other y, or vice vera. Provide both ways as different functions in your program