On the surface of the Moon, an astronaut can jump higher because the force

of gravity is less than it is on Earth. When a certain astronaut jumps, his height,

in metres above the Moon's surface, can be modelled by $s(t)=t(-\frac{5}{6}t+1),$

where $t$ is measured in seconds. What is the acceleration due to gravity on the

Moon?

Answer rating: 100% (QA)

The function st t56t 1 represents the height of the astronaut above the moons surface at any given t... View the full answer