Question: Once again simple plug and play but I am getting it wrong, help? For the limit below, evaluate the function at 0.1, 0.01, and 0.001

Once again simple plug and play but I am getting it wrong, help?

Once again simple plug and play but I am getting it wrong,

For the limit below, evaluate the function at 0.1, 0.01, and 0.001 from both sides of the value it approaches. From these values, determine the limit. Then, by using an appropriate change of algebraic form, evaluate the limit directly. lim M x>0 x2 Complete the table below to evaluate the function at 0.1 , 0.01 , and 0.001 from both sides of the value it approaches. x | o.1 o.o1 | o.oo1 | 0.001 | 0.01 | 0.1 '00 | | | | | (Type integers or decimals.) Evaluate the limit using these table values and directly. , x3 + 2x2 IIm = x->0 x2

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