One assumption made in this experiment is that $[S_2{O}_8^{2-}]>[S_2{O}_3^{2-}].$ To determine if this assumption is correct, calculate the ratio of $\frac{S_2{O}_8^{2-}}{S_2{O}_3^{2-}}$ for Trial $3.$ In Trial $3,$ the $S_2{O}_8^{2-}$ was lowest; therefore, the ratio $\frac{S_2{O}_8^{2-}}{S_2{O}_3^{2-}}$ is the smallest.

$\frac{[S_2{O}_8^{2-}]}{[S_2{O}_3^{2-}]}=$

A second assumption made in this experiment is that only a small amount of $S_2{O}_8^{2-}$ was used during the time trial, so the concentration of this reactant did not change appreciably during the course of the reaction. Calculate how much $S_2{O}_8^{2-}$ was remaining at the end of Trial $3.$

$[S_2{O}_8^{2-}]=$

Calculate the percentage of $S_2{O}_8^{2-}$ remaining at the end of Trial $3.$

$\%S_2{O}_8^{2-}$ remaining: