Question: One field representative services five customers for a computer manufacturer. Customers request assistance at an average (Poissondistributed) rate of once every six workdays. The field

One field representative services five customers for a computer manufacturer. Customers request assistance at an average (Poissondistributed) rate of once every six workdays. The field representative can handle an average (Poisson-distributed) of two call per day. Refer to the for D and F values. a. The expected number of customers waiting. (Round the final answer to 3 decimal places.) Waiting customers b. The average length of time customers must wait from the initial request for service until the service has been completed. (Round the final answer to 2 decimal places.) Average time days c. The percentage of time the service rep will be idle, i.e., the probability that a customer will not have to wait. (Round the final answer to 1 decimal place.) Idle percentage % d. By how much would your answer to part a be reduced if a second field rep were added? (Round the final answer to 3 decimal places.) fewer customers will be waiting on average. One field representative services five customers for a computer manufacturer. Customers request assistance at an average (Poissondistributed) rate of once every six workdays. The field representative can handle an average (Poisson-distributed) of two call per day. Refer to the for D and F values. a. The expected number of customers waiting. (Round the final answer to 3 decimal places.) Waiting customers b. The average length of time customers must wait from the initial request for service until the service has been completed. (Round the final answer to 2 decimal places.) Average time days c. The percentage of time the service rep will be idle, i.e., the probability that a customer will not have to wait. (Round the final answer to 1 decimal place.) Idle percentage % d. By how much would your answer to part a be reduced if a second field rep were added? (Round the final answer to 3 decimal places.) fewer customers will be waiting on average
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