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A leaky capacitor loses 21% of its charge in 8.5 min. What is the effective time constant of the system? The time constant, T = C] Units . What fraction of charge (in %) will be on the capacitor after 34 min? The charge, 3 X 100% = [jumt_. 0 After what time there will be 2% of the initial charge left on the capacitor? The time, t = C] Uiur \\/ Select an answer Question Help: 8 Messag Submit Question a forum no units required