onnections Between Multiplication Algorithms Problems 2 through 5 are some different ways students could do the multiplication problem 17 23. Make sure you understand each strategy. Then, for each, 1. a) Solve 27 12 using each student's strategy. John's solution: Well, 17 groups of 23 is the same as 17 groups of 20 and 17 more groups of 3. And 17 groups of 20 is like 10 groups of 20 and then 7 more groups of 20. 10 groups of 20 is 200, and 7 groups of 20 is 140, so that's 340. But then 17 groups of 3 is10groupsof3and7moregroupsof3. 10groupsof3is30,and7groupsof3is21,so that' 51. 340 and 51 makes 391