Question: Optimisation: A cardboard hex with 110 front a equate base and to]: must have a volume of 1200 cm3. What are the dimensions of the

Optimisation: A cardboard hex with 110 front a equate base and

Optimisation: A cardboard hex with 110 front a equate base and to]: must have a volume of 1200 cm3. What are the dimensions of the hm: that mimmme the surface area

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Optimisation: A cardboard hex with 110 front a equate base and to]: must have a volume of 1200 cm3. What are the dimensions of the hm: that mimmme the surface area

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