OPTIMIZATION:

Maximize P = 400x, + 300x2 Subject to 4x1 + 6*2 $ 720 6x1 + 3x2 5 480 *1 2 20 *2 > 30 The final tableau is: Basic X1 X2 X3 X4 X5 X6 RHS Z 0 25 50 0 0 42000 X6 0 0 0 1 70 XE O 0 10 C X1 0 0 30 X2 0 1 0 0 100 Determine for each of the following changes if the tableau remains optimal or if additional pivots will be needed. In each case explain why and show your calculations. a. Constraint 2 is changed to 6x1 + 3x2