# order and "new$\_$string" to hold the "input$\_$string" minus the

# spaces between words, if any are found.

new$\_$string $=\text{'}$

reverse$\_$string $="\text{'}"$

# Complete the for loop to iterate through each letter of the

# "input$\_$string"

for letter in input$\_$string:

# The if$-$statement checks if the "letter" is not a space.

if letter $!=""$:

# If True, add the "letter" to the end of "new$\_$string" and

# to the front of "reverse$\_$string". If False $($if a space

# is detected$),$ no action is needed. Exit the if$-$block.

new$\_$string $=$ new$\_$string $+$ letter

reverse$\_$string $=$ letter $+$ reverse$\_$string

# Complete the if$-$statement to compare the "new$\_$string" to the

# "reverse$\_$string". Remember that Python is case$-$sensitive when

# creating the string comparison code.

if new$\_$string $==$ reverse$\_$string:

# If True, the "input$\_$string" contains a palindrome.

return True

# $0$therwise, return False.

return False

print$($is$\_$palindrome$("$Never Odd or Even"$))$ # Should be True

print$($is$\_$palindrome$("$abc$"))$ # Should be False