Question: Ordinary Differential Equations Question Help!!! If y solves the initial value problem Jy' = (1+ y3/2) x y(0) = 1 find an upper bound on

Ordinary Differential Equations Question Help!!!

If y solves the initial value problem Jy' = (1+ y3/2) x y(0) = 1 find an upper bound on y Hint: it might help to observe that y' > 0 for > > 0, slightly increase the RHS of the ODE to compare y with a larger function w, and then do separation of variables to find w and upper bound it. The last problem might help with this one too

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