Original Problem:

You can build either tables or chairs using 8 large and 12 small Legos. You can't make a large from 2 smalls. Each table takes 2 large and 2 small Legos. Each chair takes 1 large and 2 small Legos.

Suppose you are given another 10 medium legos and you can make a TV stand by using 2 large legos and 4 medium legos. You can sell each TV stand for $12.

Please answer the questions based on the original lego problem and the above additional information. Note each question is independent.

1. Which constraint(s) are forming optimal solutions? (Hint: binding vs. non-binding)

Select one or more:

a.Large legos

b.Small legos

c.Medium legos

1. If you can sell chairs for $12 each, will the optimal solution change?

Select one:

a.Yes, it will change.

b.No, it won't change.

1. What is the upper bound of TV stand's range of optimality?

Answer:

1. If you were given 5 more pieces of medium legos, can you make more or less profit?

Select one:

a.More profit

b.Less profit

c.The same

1. If you were given only 9 pieces of small legos, what is the optimized/maximum profit? (now is $72)

Answer: