Question: Solve the following initial value problems: ty 1+12 subject to y(0) = -1 b. td-y-t, subject to y(1) = 1 dy = -yt-y +

Solve the following initial value problems: ty 1+12 subject to y(0) = -1 b. td-y-t, subject to y(1) = 1 dy = -yt-y + 3t + 3, subject to y(0) = 0 dt a. C. dt
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