Question: Our objective is to construct a function, P(n), such that P(n) equals the area (or integral value) of the second integral for any given n.

Our objective is to construct a function, P(n), such that P(n) equals the area (or integral value) of the second integral for any given n. This is done in order to locate the max value of P(n) for 0<=n<=1 and show that it has an upper bound of 1/48. The process will then be repeated for P_1(n) being the which equals the area (or integral value) of the first integral for any given n. The superposition of these functions will show that the function at its maximum equals 1/48 and is thus the upper bound for the original integral from 0 to 1

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