Question: P 2 Ans: c ) - 1 . 5 5 5 5 i n , + 0 . 2 3 0 4 4 rad, +

P2 Ans: c)-1.5555in,+0.23044rad,+0.34559in
Stepped cantilever beam with a square cross section has a free
end at A, is fixed at D and loaded at A with the bending moment
M0 and at C with point load P. Given: L=12.0in,M0=400.0lb-
in,P=100.0lb,E=16.0Msi,v=0.3,I=0.001736in4.
a) with Principle of Stationary Potential energy derive
symbolically (by hand) expression for vertical deflection and
rotation at point A and vertical deflection at point C.
b) use Matlab (Symbolic Math Toolbox) to verify your results from step (a)(show the code and output),
c) use the values given in the problem and calculate values of vertical deflection and rotation at point A and vertical
deflection at point C with the expressions derived in step (a).
P3 Ans: c)+0.081002 rad
Statically indeterminate beam with a square cross section is fixed
at C, supported by roller at B and loaded at its free end A with
the bending moment M0. Given: L=36.0in,M0=100.0lb-in,E=
16.0Msi,v=0.3,I=0.001736in4.
a) with Principle of Stationary Potential energy to derive
symbolically (by hand) expression for rotation at point A.
b) use Matlab (Symbolic Math Toolbox) to verify your result from step (a)(show the code and output),
c) use the values given in the problem and calculate value of rotation at point A with the expression derived in step (a).
P4 Ans: c)6.75lb,-117.0lb-in,-0.0778in
Statically indeterminate beam with square cross section is fixec
at D, supported by roller at A and loaded at B with point load P
Point C is able to move vertically, but not rotate. Given: L=
48.0in,P=15.0lb,E=10.0Msi,v=0.3,I=0.0108in4.
a) with Principle of Stationary Potential energy to derive
symbolically (by hand) expression for vertical reaction at A
and moment reaction at C. Next, obtain expression for
vertical displacement at B,
c) use the values given in the problem and calculate the reactions at A and C and the displacement at B with the expressions derived in step (a).
P 2 Ans: c ) - 1 . 5 5 5 5 i n , + 0 . 2 3 0 4 4

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