Question: P 3 = 1 0 MPa, P 4 = 0 . 0 1 MPa, E = 0 . 8 3 , C = 0 .

P3=10MPa,P4=0.01MPa,E=0.83,C=0.84. The What is Q(kJ/kg) for the power plant side of the condenser (use the correct sign)? Your answer must be within +-5.output of the plant is to be 69MW.
This problem will solve the Rankine cycle by stepping around the cycle. The 19 parts to this problem will be presented one-at-a-time.
 P3=10MPa,P4=0.01MPa,E=0.83,C=0.84. The What is Q(kJ/kg) for the power plant side of

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