P $5\mathrm{.}72$

The voltage across a load is v$($t$)=1042$cos$($t$+10)$Vv$($t$)=1042$cos$($t$+10)$V$,$ and the current through the load is i$($t$)=242$cos$($t$20)$Ai$($t$)=242$cos$($t$20)$A$.$ The reference direction for the current points into the positive reference for the voltage.