Question: P = $600 r = 6.25% t = 5 months $187.50 $17.05 $615.63 $15.63 P = $140 r-4% t = 3 years $12.00 $16.80 $156.80

 P = $600 r = 6.25% t = 5 months $187.50

P = $600 r = 6.25% t = 5 months $187.50 $17.05 $615.63 $15.63 P = $140 r-4% t = 3 years $12.00 $16.80 $156.80 $5.60 principal P is borrowed at simple interest rate r for a period of time t Find the loan's future value, A. or the total due at time t. Round answer to the nearest cent. P = $160, r = 7%, t = 3 years $171.20 $1033.60 $181.00 $193.60 P = $500, r = 6.25%, t = 7 months $718.75 $523.23 $518.23 $519.89 P is borrowed and the loan's future value. A, at time t is given. Determine the loan's simple interest tenth of a percent. P = $140, A = $190.40, t = 4 years 18% 5.5% 9.4% 9% lessthanorequalto the present value, P, you must invest to have the future value. A, at simple interest rate r after time to the nearest dollar. A = $204.80, r = 7%, t - 4 years $164.70 $164 $160 $167 represents an amount of money deposited in a savings account subject to compound interest at the how much money will be in the account after the given number of years (Assume 360 days in a year rest was earned. 91 + r)^nt P = A/(1 + r)^nt A = Pe^rt Y = (1 + r0^n - 1 Principal: $8000 Rate: 4% Compounded: semiannually Time: 5 years amount in account: $11, 841.95; interest earned: $3841.95 amount in account $9733.22; interest earned: $1733.22 amount in account: $8832.65; interest earned: $832.65 amount in account: $9751.96; interest earned: $1751.96

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