$($:$p^{\text{O}\text{I}\text{t}}=-log[O{H}^{-}]p^{OH}=-log(3\mathrm{.}2{10}^{-8})p\}$

$($b$)$ The autoionization constant of water, $K_w,$ is defined as and the $p{K}_w$ is defined as $p{K}_w=-log{K}_w.$ What is the relationship between $p{K}_w,$pOH and $pH?$

p $K_{}=-log{k}_{},\frac{p}{k_w},O{H}_{1}H+=(-log{K}_{})(-log[O{H}^{-}])(-log[H^{+}])$